RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    In AC circuit\[E={{E}_{0}}sin\]at and\[I={{I}_{0}}sin\]\[\left( \omega t-\frac{\pi }{2} \right)\]then power dissipated will be

    A)  zero            

    B)  \[\frac{{{E}_{0}}{{I}_{0}}}{2}\]

    C)  \[{{E}_{rms}}{{I}_{rms}}\]         

    D)  None of these

    Correct Answer: A

    Solution :

     Power dissipated\[P={{E}_{rms}}{{I}_{rms}}\cos \phi \] \[={{E}_{rms}}{{I}_{rms}}\cos \frac{\pi }{2}=0\]


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