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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    The potential difference on capacitor of 4.5 \[\mu \]F

    A)  8 V              

    B)  4 V                 

    C)  2 V                             

    D)  6 V             

    Correct Answer: A

    Solution :

     Equivalent capacity of combination \[\frac{1}{C}=\frac{1}{4.5}+\frac{1}{(6+3)}\] \[\Rightarrow \] \[C=3\mu F\] Therefore charge on capacitance of capacity \[4.5\mu F\] \[q=3\times 12=36C\] \[\therefore \]Potential difference on capacitance of capacity \[4.5\mu F\] \[V=\frac{q}{C}\] \[=\frac{36}{4.5}=8V\]


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