A) \[1.2\times {{10}^{11}}N/{{m}^{2}}\]
B) \[4.2\times {{10}^{11}}N/{{m}^{2}}\]
C) \[10.8\times {{10}^{-19}}N/{{m}^{2}}\]
D) \[2.4\times {{10}^{10}}N/{{m}^{2}}\]
Correct Answer: A
Solution :
Young's modulus\[Y=\frac{k}{{{r}_{0}}}\] where k = interatomic force constant \[k=3.6\times {{10}^{-19}}N/\overset{o}{\mathop{\text{A}}}\,\] or \[k=3.6\times 10N/m\] \[\therefore \] \[Y=\frac{3.6\times 10}{3\times {{10}^{-10}}}\] \[Y=1.2\times {{10}^{11}}N/{{m}^{2}}\]
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