A) \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}\]
B) \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-{{C}_{6}}{{H}_{5}}\]
C) \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{(C{{H}_{3}})}_{3}}\]
D) \[{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-H\]
Correct Answer: A
Solution :
\[\alpha -H\]containing carbonyl
group shows keto-enol isomerism. \[\underset{keto}{\mathop{{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}}}\,\underset{enol}{\mathop{{{C}_{6}}{{H}_{5}}-\underset{\begin{smallmatrix} || \\ OH \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{2}}}}\,\]
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