A) 0
B) \[-2\]
C) 4
D) 2
Correct Answer: D
Solution :
Let \[I=\int_{-1}^{1}{|1-x|dx}\] For, \[-1\le x\le 1\] \[\therefore \] \[I=\int_{-1}^{1}{(1-x)dx}\] \[=\left[ x-\frac{{{x}^{2}}}{2} \right]_{-1}^{1}=1-\frac{1}{2}+1+\frac{1}{2}=2\]
You need to login to perform this action.
You will be redirected in
3 sec
