A) \[\left[ \begin{matrix} 4 & 4 \\ 7 & 2 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 2 & 2 \\ 7/2 & 1 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 3 & -1 \\ 7/2 & 2 \\ \end{matrix} \right]\]
D) None of these
Correct Answer: B
Solution :
\[2x-\left[ \begin{matrix} 1 & 2 \\ 7 & 4 \\ \end{matrix} \right]=\left[ \begin{matrix} 3 & 2 \\ 0 & -2 \\ \end{matrix} \right]\] \[\Rightarrow \] \[2x=\left[ \begin{matrix} 3 & 2 \\ 0 & -2 \\ \end{matrix} \right]+\left[ \begin{matrix} 1 & 2 \\ 7 & 4 \\ \end{matrix} \right]\] \[\Rightarrow \] \[2x=\left[ \begin{matrix} 4 & 4 \\ 7 & 2 \\ \end{matrix} \right]\] \[\Rightarrow \] \[x=\frac{1}{2}\left[ \begin{matrix} 4 & 4 \\ 7 & 2 \\ \end{matrix} \right]\] \[\Rightarrow \] \[x=\left[ \begin{matrix} 2 & 2 \\ \frac{7}{2} & 1 \\ \end{matrix} \right]\]
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