A) \[\pi /2\]
B) \[\pi /3\]
C) \[\pi /4\]
D) \[\pi /6\]
Correct Answer: C
Solution :
\[T=\frac{2u\sin \theta }{g}\] \[R=\frac{{{u}^{2}}\sin 2\theta }{g}\] According to question, \[R=5{{T}^{2}}\] \[\frac{{{u}^{2}}\sin 2\theta }{g}=5{{\left( \frac{2u\sin \theta }{g} \right)}^{2}}\] \[\frac{2{{u}^{2}}\sin \theta .\cos \theta }{g}=\frac{20{{u}^{2}}{{\sin }^{2}}\theta }{g}\] \[\cos \theta =\frac{10\sin \theta }{{{g}^{2}}}\] \[\tan \theta =1\]or \[\theta =\frac{\pi }{4}\]
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