A) \[\frac{{{v}_{0}}^{2}}{4g}\]
B) \[\frac{{{v}_{0}}^{2}}{8g}\]
C) \[\frac{{{v}_{0}}^{2}}{g}\]
D) \[\frac{4{{v}_{0}}^{2}}{g}\]
Correct Answer: B
Solution :
From conservation of momentum, \[m{{v}_{0}}=(m+m)v'\] \[v'=\frac{{{v}_{0}}}{2}\] Again from conservation of energy, \[\frac{1}{2}(2m)v{{'}^{2}}=(2m)gh\] \[h=\frac{mv{{'}^{2}}}{2mg}=\frac{v_{o}^{2}}{8g}\]
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