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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    1 cm 3 water at 1 atm pressure and\[100{}^\circ C\] converts into\[1671\text{ }c{{m}^{3}}\]steam by taking 54 cal heat. The work done (in cal) during this process will be

    A)  400             

    B)  40

    C)  540             

    D)  None of these

    Correct Answer: B

    Solution :

     \[W=p\Delta V\] \[=1\times {{10}^{5}}[1671\times {{10}^{-6}}-1\times {{10}^{-6}}]\] \[=167J\] \[=\frac{167}{4.18}cal\] \[=40\,cal\]


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