A) \[C{{H}_{3}}-C{{H}_{2}}N{{H}_{2}}\]
B) \[C{{H}_{3}}-N{{H}_{2}}\]
C) \[C{{H}_{3}}-Cl\]
D) \[C{{H}_{3}}-Mg-N{{H}_{2}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}MgCl+N{{H}_{2}}Cl\xrightarrow[{}]{{}}C{{H}_{3}}N{{H}_{2}}+MgC{{l}_{2}}\] This is substitution reaction of Grignard's reagent.
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