RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    Methane + 10%\[{{O}_{2}}\xrightarrow[Cu\,tube]{200{}^\circ C}\]Product; product will be

    A)  \[C{{H}_{3}}OH\]

    B)  \[HCHO\]

    C)  \[C{{H}_{3}}CHO\]

    D)  \[{{C}_{2}}{{H}_{5}}CHO\]

    Correct Answer: A

    Solution :

     \[\underset{methane}{\mathop{C{{H}_{4}}}}\,+10%{{O}_{2}}\xrightarrow[Cu-tube]{200{}^\circ C}\underset{methanol}{\mathop{C{{H}_{3}}-OH}}\,\]v


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