A) 2.3 erg
B) \[3.37\times {{10}^{-12}}erg\]
C) \[4.1\times {{10}^{-8}}erg\]
D) \[1.5\times {{10}^{-2}}erg\]
Correct Answer: B
Solution :
\[E=\frac{hc}{\lambda }=\frac{6.625\times {{10}^{-27}}\times 3\times {{10}^{10}}}{5890\times {{10}^{-8}}}\] \[=3.37\times {{10}^{-12}}erg\]
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