A) \[(-\infty ,-2)\cup (1,\infty )\]
B) \[R-[-1,1]\]
C) \[(-\infty ,-2)\cup (2,\infty )\]
D) \[(-\infty ,1)\cup (2,\infty )\]
Correct Answer: A
Solution :
\[f(x)=\frac{1}{\sqrt{(x+2)(x-1)}}\] For the domain of\[x,\] \[(x+2)(x-1)>0\] \[\Rightarrow \] \[(x+2)<0,\text{ (}x-1)>0\] \[\Rightarrow \] \[x<-2,x>1\] Range is \[(-\infty ,-2)\cup (1,\infty )\]
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