A) \[\frac{1}{6}\]
B) \[\frac{3}{36}\]
C) \[\frac{1}{36}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
Number of ways of getting the same digit on all the three dice {(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5) and (6, 6, 6)} Total number of ways \[={{6}^{3}}=216\] Thus, required probability \[=\frac{6}{216}=\frac{1}{36}\]
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