RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    Moment of inertia of a thin circular ring of mass M and radius R about any diameter is

    A)  \[M{{R}^{2}}\]           

    B)  \[2M{{R}^{2}}\]

    C)  \[\frac{M{{R}^{2}}}{2}\]

    D)  \[\frac{M{{R}^{2}}}{4}\]

    Correct Answer: C

    Solution :

     The moment of inertia of circular ring about any diameter is\[\frac{1}{2}M{{R}^{2}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner