A) p
B) 16p
C) 4p
D) 32 p
Correct Answer: D
Solution :
\[{{p}_{1}}V_{1}^{\gamma }={{p}_{2}}V_{2}^{\gamma }\]constant Here, \[{{p}_{1}}=p,{{V}_{1}}=V\]and \[{{V}_{2}}=\frac{V}{8}\] \[\therefore \] \[P{{V}^{\gamma }}={{p}_{2}}{{\left( \frac{V}{8} \right)}^{\gamma }}\] \[\Rightarrow \] \[{{p}_{2}}={{8}^{\gamma }}p={{8}^{5/3}}p=32p\]
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