RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The equation of wave is\[y=5\text{ }sin\text{ }n\text{ }(t+4)\]. The amplitude and time period will be

    A)  5 cm, 2s        

    B)  5 cm, \[\frac{1}{2}\]s

    C)  5 cm, 4s        

    D)  5 cm, \[\frac{1}{4}\]s

    Correct Answer: A

    Solution :

     \[y=5\sin (\pi t+4\pi )\] The amplitude of wave = 5 cm The time period of wave \[=\frac{2\pi }{\omega }=\frac{2\pi }{\pi }\] \[=2s\]


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