RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    In R-L-C circuit,\[R=100\text{ }\Omega ,\text{ }L=1\text{ }H,\text{ }C=10\mu F\] and \[\omega \]= 314 rad /s, then find the value of impedance.

    A)  100 \[\Omega \]            

    B)  272.6 \[\Omega \]

    C)  217.2 \[\Omega \]          

    D)  205.5\[\Omega \]

    Correct Answer: A

    Solution :

     \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}\] \[=\sqrt{{{R}^{2}}+{{\left( \omega L-\frac{1}{\omega C} \right)}^{2}}}\] \[=\sqrt{{{(100)}^{2}}+{{\left( 314-1-\frac{1}{314\times 10\times {{10}^{-6}}} \right)}^{2}}}\]\[=100\,\Omega \]


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