A) \[\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}Br\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\]
D) \[\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,-C{{H}_{2}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\]
Correct Answer: C
Solution :
\[\underset{propene}{\mathop{C{{H}_{3}}-CH=C{{H}_{2}}}}\,+HBr\to \underset{2\text{ }-bromo\text{ }propane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}}}\,\]
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