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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The concentration of a acidic solution is 0.1 M and degree of dissociation is 1%. The dissociation constant of acid will be

    A)  \[1.01\times {{10}^{-5}}\]

    B)  \[1.01\times {{10}^{-3}}\]

    C)  \[1.01\times {{10}^{3}}\]

    D)  \[1.01\times {{10}^{5}}\]

    Correct Answer: A

    Solution :

     \[{{\alpha }^{2}}=KV=\frac{K}{C}\] \[K={{\alpha }^{2}}C\] \[\alpha =1%=0.01\] \[K={{(0.01)}^{2}}\times 0.1\] \[=1\times {{10}^{-5}}\]


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