A) alkane
B) alkene
C) alkyne
D) All of these
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} ethylene \\ bromide \end{smallmatrix}}{\mathop{\underset{C{{H}_{2}}Br}{\overset{C{{H}_{2}}Br}{\mathop{|}}}\,}}\,+Zn\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} \,\,\,\,ethene \\ (alkene) \end{smallmatrix}}{\mathop{\underset{C{{H}_{2}}}{\overset{C{{H}_{2}}}{\mathop{||}}}\,}}\,+ZnB{{r}_{2}}\]
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