A) \[CC{{l}_{4}}\]
B) \[C{{H}_{2}}C{{l}_{2}}\]
C) \[CHC{{l}_{3}}\]
D) \[C{{H}_{3}}Cl\]
Correct Answer: C
Solution :
Chloroform\[(CHC{{l}_{3}})\]forms chloropicrin on reaction with cone.\[HN{{O}_{3}}\].
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