A) \[\frac{1}{2}\]
B) \[\frac{1}{{{2}^{n}}}\]
C) \[\frac{1}{{{2}^{n-1}}}\]
D) None of these
Correct Answer: A
Solution :
Total number of cases\[={{2}^{n}}\] If head occurs, odd number of times, then favourable number of cases\[={{2}^{n-1}}\] \[\therefore \]Required probability \[=\frac{{{2}^{n-1}}}{{{2}^{n}}}={{2}^{n-1-n}}\] \[={{2}^{-1}}=\frac{1}{2}\]
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