A) \[\frac{3{{x}^{2}}}{2}\]
B) \[\frac{3x}{2}\]
C) \[\frac{3}{2}x\]
D) \[\frac{3}{2x}\]
Correct Answer: B
Solution :
Let \[u={{x}^{3}},v={{x}^{2}}\] \[\therefore \] \[\frac{du}{dx}=3{{x}^{2}},\frac{dv}{dx}=2x\] Now, \[\frac{du}{dv}=\frac{du/dx}{dv/dx}=\frac{3{{x}^{2}}}{2x}=\frac{3}{2}x\]
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