RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    If the displacement of simple pendulum at any time is 0.02 m and acceleration is\[2\text{ }m/{{s}^{2}},\] then in this time angular velocity will be

    A)  100 rad/s        

    B)  10 rad/s

    C)  1 rad/s   

    D)  0.1 rad/s

    Correct Answer: B

    Solution :

     Acceleration\[|\alpha |={{\omega }^{2}}x\] Or \[\omega =\sqrt{\frac{\alpha }{x}}\] \[=\sqrt{\frac{2}{0.02}}\] \[=10\text{ }rad/s\]


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