RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    A rocket emitting sound of frequency\[4\times {{10}^{7}}Hz\]is going away from the earth with a speed of 0.2 c, frequency of sound to be heard by the listener is

    A)  \[4\times {{10}^{6}}Hz\]       

    B)  \[3.3\times {{10}^{7}}Hz\]

    C)  \[3\times {{10}^{6}}Hz\]       

    D)  \[5\times {{10}^{7}}Hz\]

    Correct Answer: B

    Solution :

     \[n'=n\left( \frac{c}{c+{{c}_{s}}} \right)\] \[=4\times {{10}^{7}}\times \left( \frac{c}{c+0.2c} \right)\] \[=3.3\times {{10}^{7}}Hz\]


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