RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    At the plate voltage of 400 V and 200 V respectively the currents are\[{{i}_{{{p}_{1}}}}\]and\[{{i}_{{{p}_{2}}}}\]respectively. The ratio\[{{i}_{{{p}_{1}}}}/{{i}_{{{p}_{2}}}}\]will be

    A)  \[1:2\]             

    B)  \[2:1\]

    C)  \[1:2\sqrt{2}\]           

    D)  \[2\sqrt{2}:1\]

    Correct Answer: D

    Solution :

     The Child equation \[{{I}_{p}}=kV_{p}^{3/2}\] \[\therefore \] \[\frac{{{I}_{{{p}_{1}}}}}{{{I}_{{{P}_{2}}}}}=\frac{{{({{V}_{{{P}_{1}}}})}^{3/2}}}{{{\left( {{V}_{{{P}_{2}}}} \right)}^{3/2}}}={{\left( \frac{400}{200} \right)}^{3/2}}=\frac{2\sqrt{2}}{1}\]


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