A) 4 : 1
B) 2 : 1
C) 1 : 2
D) 1 : 4
Correct Answer: A
Solution :
The number of half year for first element \[{{n}_{1}}=\frac{2\times 24}{12}=4\] The number of half year for second element \[{{n}_{1}}=\frac{2\times 24}{16}=3\] \[\therefore \] \[\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{{{N}_{{{0}_{1}}}}{{(2)}^{{{n}_{1}}}}}{{{N}_{{{0}_{2}}}}{{(2)}^{{{n}_{2}}}}}\] \[=\frac{2}{1}.\frac{{{2}^{4}}}{{{2}^{3}}}=4\] \[{{N}_{1}}:{{N}_{2}}=4:1\]
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