A) S will run faster than P
B) P will run faster than S
C) They will both run at the same rate as on the earth
D) None of the above
Correct Answer: B
Solution :
The time period\[\left( T=2\pi \sqrt{\frac{m}{k}} \right)\]of spring watch will be remain same. While the time period\[\left( T=2\pi \sqrt{\frac{l}{g}} \right)\]of pendulum watch will be decrease. \[\left( \because g=G\times \frac{4}{3}\pi R\rho \right)\]
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