A) \[<{{c}_{H}}>=\sqrt{2}~<{{c}_{He}}>\]
B) \[<{{c}_{H}}>=<{{c}_{He}}>\]
C) \[<{{c}_{H}}>=2<{{c}_{He}}>\]
D) \[<{{c}_{H}}>=\frac{<{{c}_{He}}>}{2}\]
Correct Answer: A
Solution :
\[{{c}_{H}}=\sqrt{\frac{8\,pV}{\pi M}}\] \[=\sqrt{\frac{8\times 1\times V}{\pi \times 1}}\] \[{{c}_{He}}=\sqrt{\frac{8\times 2\times V}{\pi \times 4}}\] \[\therefore \] \[{{c}_{H}}=\sqrt{2}{{c}_{He}}\]
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