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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The alternating currents respectively are \[{{I}_{1}}={{I}_{0}}\] and   and\[{{I}_{2}}={{I}_{0}}\]\[\cos (\omega +\phi ).\]of its root mean square is

    A)  1 : 1            

    B)  1 : \[\phi \]

    C)  1 : 2             

    D)  None of these

    Correct Answer: A

    Solution :

     \[{{I}_{rm{{s}_{1}}}}=\frac{{{I}_{01}}}{\sqrt{2}}=\frac{{{I}_{0}}}{\sqrt{2}}\] \[{{I}_{rm{{s}_{2}}}}=\frac{{{I}_{02}}}{\sqrt{2}}=\frac{{{I}_{0}}}{\sqrt{2}}\] \[{{I}_{rm{{s}_{1}}}}:{{I}_{rm{{s}_{2}}}}=1:1\]


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