A) \[1\times {{10}^{5}}\]
B) \[1\times {{10}^{-10}}\]
C) \[1\times {{10}^{-5}}\]
D) \[1\times {{10}^{-10}}\]
Correct Answer: C
Solution :
\[CaS{{O}_{4}}C{{a}^{2+}}+SO_{4}^{2-}\] \[{{K}_{sp}}={{S}^{2}}\] where,\[{{K}_{sp}}=\]solubility product \[S=\]solubility \[\because \] \[{{K}_{sp}}=1\times {{10}^{-10}}\] \[\therefore \] \[{{S}^{2}}=1\times {{10}^{-10}}\] \[S=1\times {{10}^{-5}}\] Hence, solubility or concentration of \[C{{a}^{2+}}\]ion is\[1\times {{10}^{-5}}\].
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