RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    In the reaction \[H{{C}_{2}}O_{4}^{-}+PO_{4}^{3-}HPO_{4}^{2-}+{{C}_{2}}O_{4}^{2-}.\]Bronsted base is

    A)  \[PO_{4}^{3-},{{C}_{2}}O_{4}^{2-}\]

    B)  \[PO_{4}^{3-},HPO_{4}^{2-}\]

    C)  \[H{{C}_{2}}O_{4}^{-},HPO_{4}^{2-}\]

    D)  \[H{{C}_{2}}O_{4}^{-},{{C}_{2}}O_{4}^{2-}\]

    Correct Answer: A

    Solution :

     \[\underset{acid}{\mathop{H{{C}_{2}}O_{4}^{-}}}\,+\underset{base}{\mathop{PO_{4}^{3-}}}\,\underset{\begin{smallmatrix}  conjugated \\  \,\,\,\,\,\,\,acid \end{smallmatrix}}{\mathop{HPO_{4}^{2-}}}\,+\underset{\begin{smallmatrix}  conjugated \\  \,\,\,\,\,\,\,\,base \end{smallmatrix}}{\mathop{{{C}_{2}}O_{4}^{2-}}}\,\] Hence,\[PO_{4}^{3-}\]and\[{{C}_{2}}O_{4}^{2-}\]are Bronsted base.


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