RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    Ethyl acetate reacts with hydrazine to give

    A)  \[C{{H}_{3}}COONH-N{{H}_{2}}\]

    B)  \[C{{H}_{2}}COHN-NHCOC{{H}_{3}}\]

    C)  \[C{{H}_{3}}CONH-N{{H}_{2}}\]

    D)  \[C{{H}_{3}}CON{{H}_{2}}\]

    Correct Answer: C

    Solution :

     \[\underset{ethyl\text{ }acetate}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,-O{{C}_{2}}{{H}_{5}}}}\,+\underset{hydrazine}{\mathop{{{H}_{2}}N-N{{H}_{2}}}}\,\xrightarrow[{}]{{}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix}  || \\  O \end{smallmatrix}}{\mathop{C}}\,-NH-N{{H}_{2}}+{{C}_{2}}{{H}_{5}}OH\]


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