RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    If\[{{(1+i\sqrt{3})}^{9}}=a+ib,a,b\in R,\]then the value of \[b\]is

    A)  29              

    B)  \[-29\]

    C)  0               

    D)  None of these

    Correct Answer: C

    Solution :

     \[{{(1+i\sqrt{3})}^{9}}={{2}^{9}}{{\left[ \frac{1}{2}+\frac{i\sqrt{3}}{2} \right]}^{9}}\] \[={{2}^{9}}{{\left[ \cos \frac{\pi }{3}+i\sin \frac{\pi }{3} \right]}^{9}}\] \[={{2}^{9}}[\cos 3\pi +i\sin 3\pi ]\] [by De-moiver theorem] \[={{2}^{9}}[-1+i0]\] \[=-{{2}^{9}}=a+ib\] \[\Rightarrow \] \[b=0\]


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