A) 251
B) 252
C) 250
D) None of these
Correct Answer: B
Solution :
Mid term in the expansion of\[{{\left( \frac{2{{x}^{2}}}{3}+\frac{3}{2{{x}^{2}}} \right)}^{10}}\]is \[{{T}_{\frac{10}{2}+1}}{{=}^{10}}{{C}_{\frac{10}{2}}}{{\left( \frac{2{{x}^{2}}}{3} \right)}^{\frac{10}{2}}}{{\left( \frac{3}{2{{x}^{2}}} \right)}^{\frac{10}{2}}}\] \[\because \] \[\left[ {{T}_{\frac{n}{2}+1}}{{=}^{n}}{{C}_{\frac{n}{2}}}{{(x)}^{\frac{n}{2}}}{{(a)}^{\frac{n}{2}}} \right]\] \[\Rightarrow \] \[{{T}_{6}}{{=}^{10}}{{C}_{5}}{{\left( \frac{2{{x}^{2}}}{3} \right)}^{5}}{{\left( \frac{3}{2{{x}^{2}}} \right)}^{5}}\] \[\Rightarrow \] \[{{T}_{6}}{{=}^{10}}{{C}_{5}}.1\] \[\Rightarrow \] \[{{T}_{6}}=252\]You need to login to perform this action.
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