RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    If\[{{y}^{2}}+xy-{{x}^{2}}=5,\]then\[\frac{dy}{dx}\]is equal to

    A)  \[\frac{2x+y}{x+2y}\]

    B)  \[\frac{2y+x}{2x-y}\]

    C)  \[\frac{2x-y}{2y+x}\]          

    D)  None of these

    Correct Answer: C

    Solution :

    \[{{y}^{2}}+xy-{{x}^{2}}=5\] On differentiating w.r.t.\[(x),\]we get \[2y=\frac{dy}{dx}+x\frac{dy}{dx}+y-2x=0\] \[\Rightarrow \] \[\frac{dy}{dx}(2y+x)=2x-y\] \[\Rightarrow \] \[\frac{dy}{dx}=\frac{2x-y}{2y+x}\]


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