A) \[{{x}^{2}}+{{y}^{2}}-3x-4y=0\]
B) \[{{x}^{2}}+{{y}^{2}}+3x-4y=0\]
C) \[{{x}^{2}}+{{y}^{2}}-3x+4y+\frac{25}{2}=0\]
D) None of the above
Correct Answer: A
Solution :
Let equation of circle concentric to circle \[{{x}^{2}}+{{y}^{2}}-3x+4y-2=0\] is \[{{x}^{2}}+{{y}^{2}}-3x+4y+\lambda =0\] It passes through the point\[(-1,-2)\]. \[\therefore \] \[1+4+3-8+\lambda =0\] \[\Rightarrow \] \[\lambda =0\] Hence, the equation of circle is \[{{x}^{2}}+{{y}^{2}}-3x+4y=0\]
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