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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The coordinates of two points A and B are \[(-1,2)\]and\[(2,-1)\]respectively, then equation of circle AB as diameter, is

    A)  \[{{x}^{2}}+{{y}^{2}}-x+y-4=0\]

    B)  \[{{x}^{2}}+{{y}^{2}}+x+y-4=0\]

    C)  \[{{x}^{2}}+{{y}^{2}}-x-y-4=0\]

    D)  None of the above

    Correct Answer: C

    Solution :

     \[A(-1,2)\]and\[B(2,-1)\]are the end points of diameter of circle. Hence, equation of circle AB as diameter is \[(x+1)(x-2)+(y-2)(y+1)=0\] \[\Rightarrow \] \[{{x}^{2}}-2x+x-2+{{y}^{2}}+y-2y-2=0\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}+x-y-4=0\]


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