RAJASTHAN ­ PET Rajasthan PET Solved Paper-2004

  • question_answer
    The equation of a parabola is\[{{x}^{2}}=-10y,\]then coordinates of focus are

    A)  \[\left( 0,-\frac{5}{2} \right)\]

    B)  \[\left( 0,\frac{5}{2} \right)\]

    C)  \[\left( \frac{5}{2},0 \right)\]

    D)  \[\left( -\frac{5}{2},0 \right)\]

    Correct Answer: A

    Solution :

     Equation of parabola is \[{{x}^{2}}=-10y\] On comparing with \[{{x}^{2}}=-4ay\] we get           \[-4a=-10\] or \[a=\frac{10}{4}=\frac{5}{2}\] Hence, coordinates of focus \[=(0,-5/2)\]


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