A) \[2\]
B) \[\sqrt{2}\]
C) \[\frac{1}{\sqrt{2}}\]
D) 1
Correct Answer: B
Solution :
We know that, maximum value of \[a\text{ }sin\text{ }x+b\text{ }cos\text{ }x=\sqrt{{{a}^{2}}+{{b}^{2}}}\] \[\therefore \]Maximum value of \[\sin x+\cos x=\sqrt{1+1}=\sqrt{2}\]
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