A) 0.7 s
B) 0.9 s
C) 1.1 s
D) 1.4 s
Correct Answer: A
Solution :
The time period\[T=2\pi \sqrt{\frac{x}{y}}\] \[=2\pi \sqrt{\frac{0.12}{10}}\] \[=0.7\,s\]
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