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  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The magnetic field at the rate of 0.4 T/s changes in perpendicular direction from square coil of an arm 4 cm. If the resistance of coil is \[2\times {{10}^{-3}}\Omega ,\] then induced current will be

    A)  0.16 A            

    B)  0.32 A

    C)  3.2 A              

    D)  1.6 A

    Correct Answer: B

    Solution :

     \[I=\frac{1}{R}\frac{d\phi }{dt}\] \[=\frac{1}{R}\times \frac{AdB}{dt}\] \[I=\frac{1}{2\times {{10}^{-3}}}\times 16\times {{10}^{-4}}\times 0.4\] \[I=0.32\,A\]


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