A) 0.5 mm
B) 1.1 mm
C) 1.5 mm
D) 2.2 mm
Correct Answer: B
Solution :
\[x=\frac{D\lambda }{d}=\frac{20\times {{10}^{-2}}\times 54600\times {{10}^{-10}}}{0.1\times {{10}^{-3}}}\] \[=1.092\times {{10}^{-3}}m\] \[=1.1\text{ }mm\]
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