RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    Two coherent monochromatic light beam of intensities \[I\] and \[4I\] are superposed. The maximum and minimum possible intensities in the resulting beam are

    A)  \[3I\] and \[2I\]

    B)  \[25I\text{ }and\text{ }9I\]

    C)  \[9I\text{ }and\,I\]

    D)  \[5I\text{ }and\text{ }3I\]

    Correct Answer: C

    Solution :

     \[{{I}_{\max }}=I+4I+2\sqrt{I\times 4I}=9I\] \[{{I}_{\min }}=I+4I-2\sqrt{I\times 4I}=I\]


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