RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    In LCR circuit having C = 25\[\mu \]F, L = 02 H and R = 25\[\Omega \]. If a generator of E = 320 sin 314 t volt is connect in the circuit, then impedence will be

    A)  57.320\[\Omega \]          

    B)  79.480\[\Omega \]

    C)  89.50\[\Omega \]          

    D)  99.10\[\Omega \]

    Correct Answer: D

    Solution :

     \[Z=\sqrt{{{R}^{2}}+{{({{X}_{L}}-{{X}_{C}})}^{2}}}=\sqrt{{{R}^{2}}+{{\left( \omega L-\frac{1}{\omega C} \right)}^{2}}}\] \[=\sqrt{{{(25)}^{2}}+{{\left\{ 314\times 0.1-\frac{1}{314\times 25\times {{10}^{-6}}} \right\}}^{2}}}\] \[=99.1\,\Omega \]


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