A) 0.31 H
B) 0.41 H
C) 1.25 H
D) 1.75 H
Correct Answer: A
Solution :
\[{{X}_{L}}={{X}_{C}}\] \[\omega L=\frac{1}{\omega C}\] \[L=\frac{1}{{{\omega }^{2}}C}=\frac{1}{{{(314)}^{2}}\times 25\times {{10}^{-6}}}\] \[=0.41\text{ }H=0.41-0.1\] \[=0.31H\]
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