2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2005

  • question_answer
    The oxidation number of C-atom in\[C{{H}_{2}}C{{l}_{2}}\]and\[CC{{l}_{4}}\]is respectively

    A)  zero and 4       

    B)  zero and -4

    C)  2 and 4          

    D)  -2 and -4

    Correct Answer: A

    Solution :

     Let the oxidation state of C in\[C{{H}_{2}}C{{l}_{2}}\]is\[x\]. \[x+2+2(-1)=0\] \[x+2-2=0\] \[x=0\] Let the oxidation state of C in\[CC{{l}_{4}}\]is\[x\] \[x+4(x-1)=0\] \[x-4=0\] \[x=+4\] Hence, the oxidation number of C-atom in \[C{{H}_{2}}C{{l}_{2}}\]and\[CC{{l}_{4}}\]are zero and +4 respectively.


You need to login to perform this action.
You will be redirected in 3 sec spinner