A) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}CH=CH-C{{H}_{3}}\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,=C{{H}_{2}}\]
D) \[C{{H}_{3}}-C{{H}_{2}}-CH=C{{H}_{2}}\]
Correct Answer: B
Solution :
Symmetrical alkene gives only single product on ozonolysis. \[C{{H}_{3}}-CH=CH-C{{H}_{3}}\xrightarrow[(ii)Zn/{{H}_{2}}O]{(i){{O}_{2}}}2C{{H}_{3}}CHO\]
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