A) formalin
B) formaldehyde ammonia
C) hexamethylene tetraamine
D) formamide
Correct Answer: C
Solution :
\[\underset{formaldehyde}{\mathop{6HCHO}}\,+4N{{H}_{3}}\xrightarrow[{}]{{}}\] \[\underset{\begin{smallmatrix} hexamethylene \\ tetraamine\text{ }(urotropin) \end{smallmatrix}}{\mathop{{{(C{{H}_{2}})}_{6}}{{N}_{4}}}}\,+6{{H}_{2}}O\]
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